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Journal of Fluids Engineering | Volume 131 | Issue 5 | Technical Brief
Technical Briefs

Inviscid Flow Past Two Cylinders

[+] Author and Article Information
R. S. Alassar, M. A. El-Gebeily

Department of Mathematics and Statistics, King Fahd University of Petroleum & Minerals, Dhahran 31261, Saudi Arabia

J. Fluids Eng 131(5), 054501 (Apr 16, 2009) (6 pages) doi:10.1115/1.3114678 History: Received April 02, 2008; Revised March 11, 2009; Published April 16, 2009
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A simple solution of the problem of inviscid flow past two circular cylinders is presented. The two cylinders may be of different diameters and located at any distance from each other. The solutions of the two main cases, namely, when the flow is perpendicular to the center-to-center line and when the flow is parallel to it (tandem cylinders), lead to a solution of the problem when the flow is in an arbitrary direction.
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Copyright © 2009 by American Society of Mechanical Engineers
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References

Figures

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+The problem configuration
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The problem configuration
Figure 1

The problem configuration

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+Boundary conditions
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Boundary conditions
Figure 2

Boundary conditions

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+Streamline patterns for the case r1=1, r2=2, and H=4
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Streamline patterns for the case r1=1, r2=2, and H=4
Figure 3

Streamline patterns for the case r1=1, r2=2, and H=4

Grahic Jump Location
+The pressure distribution around the right cylinder for the case r1=1, r2=1
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The pressure distribution around the right cylinder for the case r1=1, r2=1
Figure 4

The pressure distribution around the right cylinder for the case r1=1, r2=1

Grahic Jump Location
+Boundary conditions for tandem cylinders
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Boundary conditions for tandem cylinders
Figure 5

Boundary conditions for tandem cylinders

Grahic Jump Location
+Streamline patterns for the case r1=4, r2=1, and H=6
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Streamline patterns for the case r1=4, r2=1, and H=6
Figure 6

Streamline patterns for the case r1=4, r2=1, and H=6

Grahic Jump Location
+The pressure distribution around the right cylinder for the case r2=1, H=6
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The pressure distribution around the right cylinder for the case r2=1, H=6
Figure 7

The pressure distribution around the right cylinder for the case r2=1, H=6

Grahic Jump Location
+Streamline patterns for the case r1=1, r2=4, H=7, and δ=π/4
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Streamline patterns for the case r1=1, r2=4, H=7, and δ=π/4
Figure 8

Streamline patterns for the case r1=1, r2=4, H=7, and δ=π/4

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